E#i0SSKrSSKJrJrJr SrSrSrg)N) frequenciespluckgetter)countby partitionbyc`[U5(d [U5n[[X55$)zCount elements of a collection by a key function >>> countby(len, ['cat', 'mouse', 'dog']) {3: 2, 5: 1} >>> def iseven(x): return x % 2 == 0 >>> countby(iseven, [1, 2, 3]) # doctest:+SKIP {True: 1, False: 2} See Also: groupby )callablerrmap)keyseqs `/home/james-whalen/.local/lib/python3.13/site-packages/ccxt/static_dependencies/toolz/recipes.pyrrs% C==Sk s3} %%c Z[[[S[R"XS955$)aQPartition a sequence according to a function Partition `s` into a sequence of lists such that, when traversing `s`, every time the output of `func` changes a new list is started and that and subsequent items are collected into that list. >>> is_space = lambda c: c == " " >>> list(partitionby(is_space, "I have space")) [('I',), (' ',), ('h', 'a', 'v', 'e'), (' ',), ('s', 'p', 'a', 'c', 'e')] >>> is_large = lambda x: x > 10 >>> list(partitionby(is_large, [1, 2, 1, 99, 88, 33, 99, -1, 5])) [(1, 2, 1), (99, 88, 33, 99), (-1, 5)] See also: partition groupby itertools.groupby r)r )r tupler itertoolsgroupby)funcr s rrrs#( ueAy00?@ AAr)r itertoolzrrr__all__rrrrrs 11 %&$Br